-5c^2+c-18=-6c^2

Solution for -5c^2+c-18=-6c^2 equation:

-5c^2+c-18=-6c^2

We move all terms to the left:

-5c^2+c-18-(-6c^2)=0

We get rid of parentheses

-5c^2+6c^2+c-18=0

We add all the numbers together, and all the variables

c^2+c-18=0

a = 1; b = 1; c = -18;
Δ = b2-4ac
Δ = 12-4·1·(-18)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{73}}{2*1}=\frac{-1-\sqrt{73}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{73}}{2*1}=\frac{-1+\sqrt{73}}{2}
$